I have got a sql database that I would like to search then display the results.
The database is called: lever
The table is called: faults
Then i have the following fields in the table:
-Incident
-Name
-Phone
I would like a user to be able to search by incident and display the results for that row.
Is anyone willing to help me out.
[php]mysql_query(‘SELECT * FROM faults WHERE incident LIKE "%’.mysql_escape_string($_GET[‘search’]).’%"’);[/php]
Thanks for that. How do I then display the results?
Whats wrong with this:
<?php // Get the search variable from URL $var = @$_GET['q'] ; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=10; // check for an empty string and display a message. if ($trimmed == "") { echo "Please enter a search...
"; exit; } // check for a search parameter if (!isset($var)) { echo "We dont seem to have a search parameter!
"; exit; } //connect to your database ** EDIT REQUIRED HERE ** mysql_connect("localhost","******","***"); //(host, username, password) //specify database ** EDIT REQUIRED HERE ** mysql_select_db("darcynet_lever") or die("Unable to select database"); //select which database we're using // Build SQL Query $query = "select * from faults where incident like "%$trimmed%" order by 1st_field"; // EDIT HERE and specify your table and field names for the SQL query $numresults=mysql_query($query); //$numrows=mysql_num_rows($numresults); // If we have no results, offer a google search as an alternative if ($numrows == 0) { echo "Sorry, your search: "" . $trimmed . "" returned zero results
"; // google echo "Click here to try the search on google
"; } // next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); // display what the person searched for echo "You searched for: "" . $var . ""
"; // begin to show results set echo "Results"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["1st_field"]; echo "$count.) $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "Showing results $b to $a of $numrows
"; ?>what is it doing/not doint?
put error_reporting(E_ALL) in the first line and tell us the errors u may get!
uncomment //$numrows=mysql_num_rows($numresults);
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/darcynet/public_html/search.php on line 35
Results
Sorry, your search: “S11835” returned zero results
Click here to try the search on google
Couldn’t execute query
to get a mysql-error use:
$numresults=mysql_query($query) or die(mysql_error());
ah great, thanks for that. Found the problem and it now seems to work and displays:
[i]You searched for: “S11835”
Results1.) S11835
Showing results 1 to 1 of 1[/i]
if i want it to show other fields from the table, where do i put them. ie start date
priority
once again thanks for your help
just use $row[“Name”] / $row[“Phone”] or however the field u wanna display is called
Hopefully this will be the last bit of help i need. I know im a bit stupid but what do I add to this:
[i]// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
$title = $row[“incident”];
$row[“person”];
$row[“Start”];
echo “$count.) $title” ;
$count++ ;
}[/i]
Dont worry i have managed to sort it. Thanks for all your help