popup not closing due to the code in parent window.

system · November 1, 2013, 1:17pm

I have two php files :-

editprofile.php : It shows the employee data like empname,email and profile picture. on profile picture column there is a link to change the profile picture . On click of this link pop-up opens(setprofilepic.php) and shows all the picture of an employee from which admin can select picture for employee profile.

I have written code to close the popup in setprofilepic.php after form submission and redirect it to parent window. It closes when there is a error in executing query on editprofile.php and redirects to the parent window but shows output on popup window if the code succesfully runs in editprofile.php

editprofile.php

[php]<?php

include (“conn.php”);

if(isset($_GET[‘action’])){
$action= $_GET[‘action’];

}
//echo $action;
if(isset($_GET[‘image_id’])){
$image_id=$_GET[‘image_id’];
}

if($action==“setprofilepic”){

$emp_id=$_GET['emp_id'];



//$profilepic = $_POST['profilepic'];
//echo "profilepic1". $profilepic;
if(isset($_POST['profilepic'])){
for ($i=0;$i<count($_POST['profilepic']);$i++){
	
	echo "count". count($_POST['profilepic']);
	
	//if(isset($_POST['profilepic'][$i])){
		
		$profilepic= $_POST['profilepic'][$i];
		
	//}
}}

echo "profilepicbahat". $profilepic;

$query5="update emp_photos set profile_picture=1 where image_id=$profilepic";
$query4="update emp_photos set profile_picture=0 where emp_id=$emp_id";
//"update emp_photos set profile_picture=1 where image_id=45";

echo $emp_id;
mysqli_query($conn,$query4) or die(mysqli_error());
mysqli_query($conn,$query5) or die('Error2, query failed');


//header('location:editprofile.php?action=edit&emp_id='.$emp_id);

if($action==“edit”){

?>
<script >
function pop_up(url){
	window.open(url,'win2','status=no,toolbar=no,scrollbars=yes,titlebar=no,menubar=no,resizable=yes,width=500,height=400,directories=no,location=no')
}
</script>
<?php 
if(isset($_POST['emp_id'])){

$emp_id= $_POST[‘emp_id’];

}
elseif(isset($_GET['emp_id'])){

$emp_id= $_GET[‘emp_id’];
}

$query1=
" SELECT employee.emp_id,employee.emp_name, employee.email,emp_photos.image_path
FROM employee, emp_photos
WHERE ((employee.emp_id =$emp_id) AND (emp_photos.emp_id =$emp_id AND emp_photos.profile_picture =1) )";

$rs= mysqli_query($conn,$query1);

$count =mysqli_num_rows($rs);

if($count>0){

while($row=mysqli_fetch_array($rs ))
{
	?>
	<table>
	<tr>
	<td> Employee Name :</td>
	<td> <input type= "text" name="emp_name" value=<?php echo $row['emp_name']?> /></td>
	</tr>
	<tr>
	<td> Email  :</td>
	<td> <input type= "text" name="email" value=<?php echo $row['email']?> /></td>
	</tr>
	<tr>
	<td>Image  :</td>
	<td> <img src=<?php echo $row['image_path']?> width="100" height="100" /></td>
	<td><a href="#" onclick=pop_up("setprofilepic.php?emp_id=<?php echo $row['emp_id']?>") >Change Profile Picture </a>
	</tr>
	</table>
	<?php 
}

}

setprofile.pic

<?php include "conn.php"; $emp_id=$_GET['emp_id']; echo $emp_id; $query="select image_id ,image_path from emp_photos where emp_id= $emp_id"; $rs=mysqli_query($conn,$query); $count= mysqli_num_rows($rs); echo $count;?> <?php while ($row = mysqli_fetch_array($rs)) {

$image_path=$row['image_path'];
$image_id=$row['image_id'];?>

<tr><td><img src=<?php echo $image_path ?> width="100" height="100" />
<input type="radio"  name=profilepic[] value="<?php echo $image_id ?>" /></td>
</tr>

<?php } ?>

[/php]

Kindly guide .