Get Selected Option Value and Insert To PHP Variable - Without refreshing.

[system]

Hi

I have a HTML form with selected option values. I am trying to get the currently selected item and store it inside a php variable to do something with it further down the page. I need to do all of this without refreshing/reloading the page (if possible).

<form method="post">
            <select name="MySelect">
                <option value="year 1">year 1</option>
                <option value="year 2">year 2</option>
                <option value="year 3">year 3</option>
            </select>
</form>

[php]

<?php if(!empty($_POST['MySelect'])) { $selected = $_POST['MySelect']; echo $selected; } [/php] To clarify the above "should" echo out the selected option everytime onchange of the selected option. Any help is appreciated, regards.

[richei]

where is the code you’re calling when the onchange fires? or is that what you’re needing?

[Strider64]

I think the OP is looking for more of JavaScript than PHP, for that will do want you want. An it is best to have a button or a submit button even if you are using JavaScript, for graceful degradation purposes.

[KHAN]

Sorry you are right i missed of some code.

<form method="post">
      <select name="MySelect" onchange=run(sel)>
                <option value="year 1">year 1</option>
                <option value="year 2">year 2</option>
                <option value="year 3">year 3</option>
      </select>
</form>

[code]
function run(sel) {

var i = sel.selectedIndex;
if (i != -1) {
    $.ajax({
        type: "POST",
        url: "index.php",
        data: { MySelect: sel.options[i].text}

    }).done(function( msg ) {});
}

}[/code]

[php]

<?php if(!empty($_POST['MySelect'])) { $selected = $_POST['MySelect']; echo $selected; } ?>

[/php]

Here is the above code, though i am struggling to echo it out because i dont believe its being stored in the $selected" variable