ok… I’m sending u the files I tried it in several places ( I commented them)…
and a image for the outcome…
qq.txt (11 KB)
ok… I’m sending u the files I tried it in several places ( I commented them)…
and a image for the outcome…
qq.txt (11 KB)
Stan,
It’s looking good, I see you added the correct POSTS to set the Variables, Congrats…
Now do this…
Before this:
[php]$custUdt=mysql_query($udtSql) or die(mysql_error());[/php]
Add this:
[php]echo $udtSql; [/php]
It should output the query, post the output so I can see it.
That’s odd, do you see that none of the information is filled in the update statement, that’s why nothing gets updated.
That means the
//echo “bbb” . $cust_id;
is blank if you un-comment that out right?
Also I noticed an HTML error
Change:
<form form id="form1" name="form1" method="post" action="">
To:
<form id="form1" name="form1" method="post">
basically this is what I need to do , right ? could you help me to print $fname inside the UPDATE.
I think if there is a way then I can use it in that original form too.
[php]
Untitled Document
<?php if(isset($_POST['submit'])) { global $fnames; $fname=$_POST['fname']; echo ''; } if(isset($_POST['go'])) { $go=$_POST['go']; echo $go; echo $fnames; } [/php]
You don’t need this statement, unless you’re using it in some other page.
[php]global $fnames;[/php]
MOVE:
[php]$fname=$_POST[‘fname’];[/php]
To above here:
[php]if(isset($_POST[‘submit’]))[/php]
Rename:
[php]echo $fnames;[/php]
to
[php]echo $fname;[/php]
Like below.
[php]
Untitled Document
<?php $fname=$_POST['fname']; if(isset($_POST['submit'])) { echo ''; } if(isset($_POST['go'])) { $go=$_POST['go']; echo $go; echo $fname; } ?>[/php]